A tangent galvanometer has a coil of 25 turns and radius of 15 ,cm. horizontal component of earth&rs

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5.Magnetism and Matter

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A tangent galvanometer has a coil of $25$ $turns$ and radius of $15 \,cm.$ The horizontal component of the earth’s magnetic field is $3 × 10^{-5}$ $T$. The current required to produce a deflection of $45^o$ in it, is.....$A$

$0.29$

$1.2 $

$3.6 \times 10^{-5} $

$0.14 $

Solution

(a)$i = \frac{{2r{B_H}}}{{{\mu _0}N}}\tan \theta $
$ \Rightarrow i = \frac{{2 \times 15 \times {{10}^{ – 2}} \times 3 \times {{10}^{ – 5}}}}{{4\pi \times {{10}^{ – 7}} \times 25}} \times \tan {45^o}$$ \Rightarrow i = 0.29\;A$

Standard 12

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Solution

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