Period of oscillation of a magnet of a vibration magnetometer is 2.45 ,s at one place and 4.9 ,s at

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5.Magnetism and Matter

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The period of oscillation of a magnet of a vibration magnetometer is $2.45 \,s$ at one place and $4.9 \,s$ at the other. The ratio of the horizontal component of earth magnetic field at the two places is .........

A

$1: 4$

B

$1: 2$

C

$2: 1$

D

$4: 1$

Solution

(d)

$2.45=2 \pi \sqrt{\frac{1}{M B_{H_1}}}$

$4.9=2 \pi \sqrt{\frac{1}{M B_{H_2}}}$

Dividing both the equations

$\frac{2.45}{4.9}=\sqrt{\frac{B_{H_2}}{B_{H_1}}} \Rightarrow \frac{B_{H_1}}{B_{H_2}}=4: 1$

Standard 12

Physics

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