Gujarati
5.Magnetism and Matter
easy

The period of oscillation of a magnet in vibration magnetometer is $2 \,sec$. The period of oscillation of a magnet whose magnetic moment is four times that of the first magnet is...$sec$

A

$1 $

B

$4$

C

$8$

D

$0.5$

Solution

(a)$\frac{{{T_1}}}{{{T_2}}} = \sqrt {\frac{{{M_2}}}{{{M_1}}}} = \sqrt {\frac{{4M}}{M}} = 2 \Rightarrow \frac{2}{{{T_2}}} = 2$$ \Rightarrow {T_2} = 1\,\sec $

Standard 12
Physics

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