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5.Magnetism and Matter
easy
The period of oscillation of a magnet in vibration magnetometer is $2 \,sec$. The period of oscillation of a magnet whose magnetic moment is four times that of the first magnet is...$sec$
A
$1 $
B
$4$
C
$8$
D
$0.5$
Solution
(a)$\frac{{{T_1}}}{{{T_2}}} = \sqrt {\frac{{{M_2}}}{{{M_1}}}} = \sqrt {\frac{{4M}}{M}} = 2 \Rightarrow \frac{2}{{{T_2}}} = 2$$ \Rightarrow {T_2} = 1\,\sec $
Standard 12
Physics