A test charge $q$ is made to move in the electric field of a point charge $Q$ along two different closed paths as per figure. First path has sections along and perpendicular to lines of electric field. Second path is a rectangular loop of the same area as the first loop. How does the work done compare in the two cases ?
The electrostatic field is conservative and in this field work done by electric force on the charge in a closed loop is zero and work done for this work depends only on the initial and final states of charged body. Hence, the work done in both the cases will be zero.
As per this diagram a point charge $ + q$ is placed at the origin $O$. Work done in taking another point charge $ - Q$ from the point $A$ [co-ordinates $(0,\,a)$] to another point $B$ [co-ordinates $(a, 0)$] along the straight path $AB$ is
State which of the following is correct
Electric field at a place is $\overrightarrow {E\,} = {E_0}\hat i\,V/m$ . A particle of charge $+q_0$ moves from point $A$ to $B$ along a circular path find work done in this motion by electric field
Figure shows a positively charged infinite wire. $A$ particle of charge $2C$ moves from point $A$ to $B$ with constant speed. (Given linear charge density on wire is $\lambda = 4 \pi \varepsilon_0$)
The ratio of momenta of an electron and an $\alpha$-particle which are accelerated from rest by a potential difference of $100\, volts$ is