Three particles, each having a charge of 10,μ C are placed at corners of an equilateral triangle of

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2. Electric Potential and Capacitance

medium

Three particles, each having a charge of $10\,\mu C$ are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is.....$J$ (Given $\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}\,N - {m^2}/{C^2}$)

$0$

Infinite

$27$

$100$

Solution

(c) For pair of charge $U = \frac{1}{{4\pi {\varepsilon _0}}}.\frac{{{q_1}{q_2}}}{r}$
${U_{System}} = \frac{1}{{4\pi {\varepsilon _0}}}\left[ {\frac{{10 \times {{10}^{ – 6}} \times 10 \times {{10}^{ – 6}}}}{{10/100}}} \right.$
$\left. { + \frac{{10 \times {{10}^{ – 6}} \times 10 \times {{10}^{ – 6}}}}{{10/100}} + \frac{{10 \times {{10}^{ – 6}} \times 10 \times {{10}^{ – 6}}}}{{10/100}}} \right]$
$ = 3 \times 9 \times {10^9} \times \frac{{100 \times {{10}^{ – 12}} \times 100}}{{10}} = 27\,J$

Standard 12

Physics

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(KVPY-2014)

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Three particles, each having a charge of $10\,\mu C$ are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is.....$J$ (Given $\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}\,N - {m^2}/{C^2}$)

Solution

Similar Questions

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