A total charge $Q$ is broken in two parts $Q_1$ and $Q_2$ and they are placed at a distance $R$ from each other. The maximum force of repulsion between them will occur, when
A total charge $Q$ is broken in two parts $Q_1$ and $Q_2$ and they are placed at a distance $R$ from each other. The maximum force of repulsion between them will occur, when
- A
${Q_2} = \frac{Q}{R},{Q_1} = Q - \frac{Q}{R}$
- B
${Q_2} = \frac{Q}{4},{Q_1} = Q - \frac{{2Q}}{3}$
- C
${Q_2} = \frac{Q}{4},{Q_1} = \frac{{3Q}}{4}$
- D
${Q_1} = \frac{Q}{2},{Q_2} = \frac{Q}{2}$
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- [AIIMS 2017]
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