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A truck running at $90\, km h ^{-1}$ is brought to rest over a distance of $25\, m$. Calculate the retardation and time for which brakes are applied.
Solution
$u=90 km h ^{-1}=25 m s ^{-1} ; v=0 ; S =25 m ; a=?$
$t=?$
$(i)$ Applying $v^{2}-u^{2}=2 a S$
$(0)^{2}-(25)^{2}=2 \times a \times 25$
$\Rightarrow$ $a=-\frac{625}{50}=-12.5 m s ^{-2}$
Therefore, retardation $=-a=12.5 m s ^{-2}$
$(ii)$ Applying $v=u+a t$
$0=25-12.5 \times t$
$12.5 t=25 \quad$ or $\quad t=2 s$
Similar Questions
A truck is moving on a straight road with uniform acceleration. The following table gives the speed of the truck at various instants of time.
Speed $\left(m s^{-1}\right)$ | $5$ | $10$ | $15$ | $20$ | $25$ | $30$ |
Time $(s)$ | $0$ | $10$ | $20$ | $30$ | $40$ | $50$ |
Draw the speed-time graph by choosing a convenient scale. Determine from it
$(i)$ the acceleration of truck
$(ii)$ the distance travelled by the truck in $50$ seconds.