A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance o

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8. FORCE AND LAWS OF MOTION

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A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of $400 \,m $ in $20\, s$. Find the force(in $N$) acting on it if its mass is $7$ tonnes ($1$ tonne $= 1000\, kg$)

$14000$

$41000$

$16000$

$11000$

Initial velocity of the truck, $u = 0\, m/s$

Time taken, $t = 20\, s$

Distance covered by the stone,$ s = 400\, m$

According to the second equation of motion:

$s=u t+\frac{1}{2} a t^{2}$

We have

$400=0 \times 20+\frac{1}{2} \times a \times(20)^{2}$

$\Rightarrow 400=200 a$

$\Rightarrow a=2\, m / s ^{2}$

Now, Force = mass $\times$ acceleration

$F=7000 \times 2=14000\, N$

Standard 9

Science

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easy

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