A uniform flexible chain of mass m and length 2l hangs in equilibrium over a smooth horizontal pin o

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5.Work, Energy, Power and Collision

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A uniform flexible chain of mass $m$ and length $2l$ hangs in equilibrium over a smooth horizontal pin of negligible diameter. One end of the chain is given a small vertical displacement so that the chain slips over the pin. The speed of chain when it leaves pin is

A

$\sqrt {2gl}$

B

$\sqrt {gl}$

C

$\sqrt {4gl}$

D

$\sqrt {3gl}$

Solution

By $COME$ decrease in $P . E=$ increse in $K . E$

$\operatorname{mg} 1-\operatorname{mg} \frac{\ell}{2} =\frac{1}{2} \mathrm{mV}^{2} $

$\mathrm{v} =\sqrt{\mathrm{g} \ell}$

Standard 11

Physics

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