A uniform meter scale balances at 40,cm mark when weights of 10,g and 20,g are suspended from 10,cm

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6.System of Particles and Rotational Motion

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A uniform meter scale balances at the $40\,cm$ mark when weights of $10\,g$ and $20\,g$ are suspended from the $10\,cm$ and $20\,cm$ marks. The weight of the metre scale is ...... $g$

A

$50$

B

$60$

C

$70$

D

$80$

Solution

By Balancing torque about $40\,cm$ mark

$30 \times 10 g+20 \times 20 g =10 \times mg$

$300+400=10\,m$

$m=70\,g$

Standard 11

Physics

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