A vertical column 50 cm long at 50°C bala | vedclass

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Question

(a) $\frac{{{h_1}}}{{{h_2}}} = \frac{{{ho _1}}}{{{ho _2}}} = \frac{{(1 + \gamma \,{	heta _1})}}{{(1 + \gamma \,{	heta _2})}}$  $\left[

Vedclass · Accepted Answer

$0.005&deg;C^{-1}$

Vedclass · Answer

(a) $\frac{{{h_1}}}{{{h_2}}} = \frac{{{ho _1}}}{{{ho _2}}} = \frac{{(1 + \gamma \,{	heta _1})}}{{(1 + \gamma \,{	heta _2})}}$  $\left[ {\because \,ho  = \frac{{{ho _0}}}{{(1 + \gamma 	heta )}}} ight]$

$\Rightarrow$ $\frac{{50}}{{60}} = \frac{{1 + \gamma 	imes 50}}{{1 + \gamma 	imes 100}}$ $\Rightarrow$  $\gamma = 0.005/^\circ C$

A vertical column $50$ $cm$ long at $50°C$ balances another column of same liquid $60 \,cm$ long at $100°C$. The coefficient of absolute expansion of the liquid is

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