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10-1.Thermometry, Thermal Expansion and Calorimetry
easy
A blacksmith fixes iron ring on the rim of the wooden wheel of a horse cart. The diameter of the rim and the iron ring are $5.243\; m$ and $5.231\; m$, respectively at $27^oC$. To what temperature (in $^oC$) should the ring be heated so as to fit the rim of the wheel?
A
$186$
B
$218$
C
$293$
D
$312$
Solution
$T_{1}=27\,^{\circ} C$
$L_{ T 1}=5.231 \,m$
$L_{T2}=5.243 \,m$
So, $L_{ T 2}=L_{ T 1}\left[1+\alpha_{1}\left(T_{2}-T_{1}\right)\right]$
$5.243 m =5.231 m \left[1+1.20 \times 10^{-5} K ^{-1}\left(T_{2}-27^{\circ} C \right)\right]$
$T_{2}=218\,^{\circ} C$
Standard 11
Physics