A vertical spring with force constant K is fixed on a table. A ball of mass m at a height h above fr

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5.Work, Energy, Power and Collision

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A vertical spring with force constant $K$ is fixed on a table. A ball of mass $m$ at a height $h$ above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance $d$. The net work done in the process is

A

$mg\,\left( {h - d} \right) + \frac{1}{2}\,K{d^2}$

B

$mg\,\left( {h + d} \right) + \frac{1}{2}\,K{d^2}$

C

$mg\,\left( {h + d} \right) - \frac{1}{2}\,K{d^2}$

D

$mg\,\left( {h - d} \right) - \frac{1}{2}\,K{d^2}$

Solution

Net work done $=$ work done by gravitational force $+$ work done by spring force

$=\operatorname{mg}(\mathrm{h}+\mathrm{d})-\frac{1}{2} \mathrm{Kd}^{2}$

Standard 11

Physics

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