Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A vertical spring with force constant $K$ is fixed on a table. A ball of mass $m$ at a height $h$ above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance $d$. The net work done in the process is

A

$mg(h - d) + \frac{1}{2}K{d^2}$

B

$mg(h + d) + \frac{1}{2}K{d^2}$

C

$mg(h + d) - \frac{1}{2}K{d^2}$

D

$mg(h - d) - \frac{1}{2}K{d^2}$

Solution

Net work done $=$ work done by gravitational force $+$ work done by spring force

$=mg(h + d) – \frac{1}{2}K{d^2}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.