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5.Work, Energy, Power and Collision
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A vertical spring with force constant $K$ is fixed on a table. A ball of mass $m$ at a height $h$ above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance $d$. The net work done in the process is
A
$mg(h - d) + \frac{1}{2}K{d^2}$
B
$mg(h + d) + \frac{1}{2}K{d^2}$
C
$mg(h + d) - \frac{1}{2}K{d^2}$
D
$mg(h - d) - \frac{1}{2}K{d^2}$
Solution
Net work done $=$ work done by gravitational force $+$ work done by spring force
$=mg(h + d) – \frac{1}{2}K{d^2}$
Standard 11
Physics
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