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(c)Initially magnetic moment of system
${M_1} = \sqrt {{M^2} + {M^2}} = 2M$ and moment of inertia
${I_1} = I + I = 2I.$
Finally when one of the mag

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$2$

Vedclass · Answer

(c)Initially magnetic moment of system
${M_1} = \sqrt {{M^2} + {M^2}} = 2M$ and moment of inertia
${I_1} = I + I = 2I.$
Finally when one of the magnet is removed then
${M_2} = M$ and ${I_2} = I$
So $T = 2\pi \sqrt {\frac{I}{{M\;{B_H}}}} $
$\frac{{{T_1}}}{{{T_2}}} = \sqrt {\frac{{{I_1}}}{{{I_2}}} 	imes \frac{{{M_2}}}{{{M_1}}}} = \sqrt {\frac{{2I}}{I} 	imes \frac{M}{{\sqrt 2 M}}} $$ \Rightarrow {T_2} = \frac{{{2^{5/4}}}}{{{2^{1/4}}}} = 2\;\sec .$

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