- Home
- Standard 11
- Physics
13.Oscillations
medium
A weightless spring which has a force constant oscillates with frequency $n$ when a mass $m$ is suspended from it. The spring is cut into two equal halves and a mass $2m $ is suspended from it. The frequency of oscillation will now become
A
$n$
B
$2n$
C
$\frac{n}{\sqrt2}$
D
$n(2)^{1/2}$
Solution
(a) $n = \frac{1}{{2\pi }}\sqrt {\frac{k}{m}} $
==>$\frac{n}{{n'}} = \sqrt {\frac{k}{m} \times \frac{{m'}}{{K'}}} $
$ = \sqrt {\frac{k}{m} \times \frac{{2m}}{{2K}}} = 1$
==> $n' = n$
Standard 11
Physics
Similar Questions
medium
easy