A spring is stretched by 5 ,mathrm{~cm} by a force 10 ,mathrm{~N} . time period of oscillations when

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13.Oscillations

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A spring is stretched by $5 \,\mathrm{~cm}$ by a force $10 \,\mathrm{~N}$. The time period of the oscillations when a mass of $2 \,\mathrm{~kg}$ is suspended by it is :(in $s$)

A

$0.0628$

B

$6.28$

C

$3.14$

D

$0.628$

(NEET-2021)

Solution

$\mathrm{F}=\mathrm{K} \mathrm{x}$

$10=\mathrm{K} \times 0.05$

$\mathrm{~K}=\frac{1000}{5}=200$

$\mathrm{~T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{k}}}=2 \pi \sqrt{\frac{2}{200}}$

$=\frac{2 \pi}{10}=\frac{6.28}{10}$

$=.628\, \mathrm{~s}$

Standard 11

Physics

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