A wire of density $8 \times 10^3\,kg / m ^3$ is stretched between two clamps $0.5\,m$ apart. The extension developed in the wire is $3.2 \times 10^{-4}\,m$. If $Y =8 \times 10^{10}\,N / m ^2$, the fundamental frequency of vibration in the wire will be $......\,Hz$.

  • [JEE MAIN 2023]
  • A

    $80$

  • B

    $60$

  • C

    $40$

  • D

    $20$

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  • [AIIMS 1999]