A wire of length 50, cm and cross sectional area of 1 sq. mm is extended by 1, mm. required work wil

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8.Mechanical Properties of Solids

medium

A wire of length $50\, cm$ and cross sectional area of $1$ sq. mm is extended by $1\, mm.$ The required work will be $(Y = 2 \times {10^{10}}\,N{m^{ - 2}})$

$6 \times {10^{ - 2}}\,J$

$4 \times {10^{ - 2}}\,J$

$2 \times {10^{ - 2}}\,J$

$1 \times {10^{ - 2}}\,J$

Solution

(c) $W = \frac{{YA{l^2}}}{{2L}} = \frac{{2 \times {{10}^{10}} \times {{10}^{ – 6}} \times {{({{10}^{ – 3}})}^2}}}{{2 \times 50 \times {{10}^{ – 2}}}}$$ = 2 \times {10^{ – 2}}\;J$

Standard 11

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medium

A wire of length $50\, cm$ and cross sectional area of $1$ sq. mm is extended by $1\, mm.$ The required work will be $(Y = 2 \times {10^{10}}\,N{m^{ - 2}})$

Solution

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