An aluminium rod with Young's modulus Y = | vedclass

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Question

$Y =7 	imes 10^{10}\,N / m ^2$

$	ext { Strain }=\frac{0.04}{100}$

$	ext { Energy }=\frac{1}{2}\left(\frac{ YA }{l}ight) \Delta x ^2$

$

Vedclass · Accepted Answer

$5600$

Vedclass · Answer

$Y =7 	imes 10^{10}\,N / m ^2$

$	ext { Strain }=\frac{0.04}{100}$

$	ext { Energy }=\frac{1}{2}\left(\frac{ YA }{l}ight) \Delta x ^2$

$	ext { Energy }=\frac{1}{2} YA \left(\frac{\Delta x }{l}ight)^2 	imes l$

$\frac{ E }{ V }=\frac{1}{2} 	imes Y 	imes \operatorname{strain}{ }^2$

$=\frac{1}{2} 	imes 7 	imes 10^{10} 	imes \frac{0.04 	imes 0.04}{10^4}=56 	imes 10^2$

An aluminium rod with Young's modulus $Y =7.0$ $\times 10^{10} N / m ^2$ undergoes elastic strain of $0.04 \%$. The energy per unit volume stored in the rod in SI unit is:

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