Activity of a radioactive substance is R_1 at | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$N=N_{0} e^{-\lambda t}$

$R=\frac{d N}{d t}=-\lambda N_{0} e^{-\lambda t}$

$R_{1}=-\lambda N_{0} e^{-\lambda t_{1}}$

$R_{2}=-\lambda N_{0} e^

Vedclass · Accepted Answer

${e^{  \lambda ({t_1} + {t_2})}}$

Vedclass · Answer

$N=N_{0} e^{-\lambda t}$

$R=\frac{d N}{d t}=-\lambda N_{0} e^{-\lambda t}$

$R_{1}=-\lambda N_{0} e^{-\lambda t_{1}}$

$R_{2}=-\lambda N_{0} e^{-\lambda t_{2}}$

Dividing the two, we get:

$R_{2}=R_{1} e^{\lambda\left(t_{1}-t_{2}\right)}$

Activity of a radioactive substance is $R_1$ at time $t_1$ and $R_2$ at time $t_2(t_2 > t_1).$ Then the ratio $\frac{R_2}{R_1}$ is :

Similar Questions

$N$ atoms of a radioactive element emit $n$ alpha particles per second. The half life of the element is

The average life $T$ and the decay constant $\lambda $ of a radioactive nucleus are related as

A radioactive sample at any instant has its disintegration rate $5000$ disintegration per minute. After $5$ minutes, the rate is $1250$ disintegrations per minute. Then, the decay constant (per minute) is

Mean life of a radioactive sample is $100$ seconds. Then its half life (in minutes) is

The curve between the activity $A$ of a radioactive sample and the number of active atoms $N$ is