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13.Nuclei
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The half-life of $B{i^{210}}$ is $5\, days$. What time is taken by $(7/8)^{th}$ part of the sample to decay.........$days$
A
$3.4$
B
$10 $
C
$15 $
D
$20 $
Solution
(c) By using$N = {N_0}{\left( {\frac{1}{2}} \right)^{t/T}};$
where $N = \left( {1 – \frac{7}{8}} \right)\,{N_0} = \frac{1}{8}{N_0}$
So $\frac{1}{8}{N_0} = {N_0}{\left( {\frac{1}{2}} \right)^{t/T}}$
==>${\left( {\frac{1}{2}} \right)^3} = {\left( {\frac{1}{2}} \right)^{t/5}}$
==> $t =15\, days.$
Standard 12
Physics
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