Gujarati
Hindi
p-Block Elements - I
medium

Aluminium chloride exists as a dimer, $Al_2Cl_6,$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

A

$Al^{3+} +3Cl^-$

B

$[Al(H_2 O)_6 ]^{3+} + 3Cl^-$

C

$[Al(OH)_6]^{3-} + 3HCl$

D

$Al_2O_3 + 6HCl$

Solution

$\mathrm{AlCl}_{3}$ is covalent but in water, it becomes ionic due to large hydration energy of $\mathrm{Al}^{3+}$.

$\mathrm{AlCl}_{3}+6 \mathrm{H}_{2} \mathrm{O} \quad \rightarrow \quad\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}_{6}\right)\right]^{3+}+3 \mathrm{Cl}^{-}$

Hence, option $\mathrm{B}$ is correct.

Standard 11
Chemistry

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