Aluminium trifluoride is insoluble in anhydrous HF but dissolves on addition of NaF . Aluminium trif

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p-Block Elements - I

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Aluminium trifluoride is insoluble in anhydrous $HF$ but dissolves on addition of $NaF$. Aluminium trifluoride precipitates out of the resulting solution when gaseous $BF $$_{3}$ is bubbled through. Give reasons.

Option A

Option B

Option C

Option D

Solution

Hydrogen fluoride $(HF)$ is a covalent compound and has a very strong intermolecular hydrogen-bonding. Thus, it does not provide ions and aluminium fluoride $(AlF)$ does not dissolve in it. Sodium fluoride $(NaF)$ is an ionic compound and when it is added to the mixture, $AlF$ dissolves. This is because of the availability of free $F^{-}$. The reaction involved in the process is:

$Al{F_3} + 3NaF \to \mathop {N{a_3}[Al{F_6}]}\limits_{Sodium\,hexafluroalu\min ate\,(III)} $

When boron trifluoride $\left( BF _{3}\right)$ is added to the solution, aluminium fluoride precipitates out of the solution. This happens because the tendency of boron to form complexes is much more than that of aluminium. Therefore, when $BF _{3}$ is added to the solution, $B$ replaces $Al$ from the complexes according to the following reaction:

$N{a_3}[Al{F_6}] + 3B{F_3} \to 3Na[B{F_4}] + Al{F_3}$

Standard 11

Chemistry

$H_3BO_3$ $\xrightarrow{{{T_1}}}X\xrightarrow{{{T_2}}}Y\xrightarrow{{red\,hot}}$ $B_2O_3$

if $T_1 < T_2$ then $X$ and $Y$ respectively are

medium

Aluminium trifluoride is insoluble in anhydrous $HF$ but dissolves on addition of $NaF$. Aluminium trifluoride precipitates out of the resulting solution when gaseous $BF $$_{3}$ is bubbled through. Give reasons.

Solution

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Solution

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Diborane $(B_2H_6)$ reacts independently with $O_2$ and $H_2O$ to produce, respectively

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$H_3BO_3$ $\xrightarrow{{{T_1}}}X\xrightarrow{{{T_2}}}Y\xrightarrow{{red\,hot}}$ $B_2O_3$

if $T_1 < T_2$ then $X$ and $Y$ respectively are