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The correct statements from the following are :
$(A)$ The decreasing order of atomic radii of group $13$ elements is $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$.
$(B)$ Down the group $13$ electronegativity decreases from top to bottom.
$(C)$ $\mathrm{Al}$ dissolves in dil. $\mathrm{HCl}$ and liberate $\mathrm{H}_2$ but conc. $\mathrm{HNO}_3$ renders Al passive by forming a protective oxide layer on the surface.
$(D)$ All elements of group 13 exhibits highly stable +1 oxidation state.
$(E)$ Hybridisation of $\mathrm{Al}$ in $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ ion is $\mathrm{sp}^3 \mathrm{~d}^2$.
Choose the correct answer from the options given below:
$(C)$ and $(E)$ only
$(A)$, $(C)$ and $(E)$ only
$(A)$, $(B)$, $(C)$ and $(E)$ only
$(A)$ and $(C)$ only
Solution
$A$. size order $\mathrm{T} \ell>\mathrm{In}>\mathrm{Al}>\mathrm{Ga}>\mathrm{B}$
$B$. Electronegativity order $\mathrm{B}>\mathrm{Al}<\mathrm{Ga}<\operatorname{In}<\mathrm{T} \ell$
$D$. $\mathrm{B}, \mathrm{Al}$ are more stable in $+3$ oxidation state
So, only $C, E$ statements are correct.
