Gujarati
14.Probability
easy

Among $15$ players, $8$ are batsmen and $7$ are bowlers. Find the probability that a team is chosen of $6$ batsmen and $5$ bowlers

A

$\frac{{{}^8{C_6} \times {}^7{C_5}}}{{{}^{15}{C_{11}}}}$

B

$\frac{{^8{C_6}{ + ^7}{C_5}}}{{^{15}{C_{11}}}}$

C

$\frac{{15}}{{28}}$

D

None of these

Solution

(a) Total number of ways $ = {\,^{15}}{C_{11}}$

Favourable cases $ = {\,^8}{C_6}$$ \times {\,^7}{C_5}$

$\therefore$ Required probability $ = \frac{{^8{C_6} \times {\,^7}{C_5}}}{{^{15}{C_{11}}}}.$

Standard 11
Mathematics

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