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14.Probability
easy
Among $15$ players, $8$ are batsmen and $7$ are bowlers. Find the probability that a team is chosen of $6$ batsmen and $5$ bowlers
A
$\frac{{{}^8{C_6} \times {}^7{C_5}}}{{{}^{15}{C_{11}}}}$
B
$\frac{{^8{C_6}{ + ^7}{C_5}}}{{^{15}{C_{11}}}}$
C
$\frac{{15}}{{28}}$
D
None of these
Solution
(a) Total number of ways $ = {\,^{15}}{C_{11}}$
Favourable cases $ = {\,^8}{C_6}$$ \times {\,^7}{C_5}$
$\therefore$ Required probability $ = \frac{{^8{C_6} \times {\,^7}{C_5}}}{{^{15}{C_{11}}}}.$
Standard 11
Mathematics