Three randomly chosen nonnegative integers $x, y$ and $z$ are found to satisfy the equation $x+y+z=10$. Then the probability that $z$ is even, is
Three randomly chosen nonnegative integers $x, y$ and $z$ are found to satisfy the equation $x+y+z=10$. Then the probability that $z$ is even, is
- [IIT 2017]
- A
$\frac{36}{55}$
- B
$\frac{6}{11}$
- C
$\frac{1}{2}$
- D
$\frac{5}{11}$
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- [IIT 2012]