Among following, molecule expected to be stabilized by anion formation is

English

Gujarati

Hindi

4.Chemical Bonding and Molecular Structure

normal

Among the following, the molecule expected to be stabilized by anion formation is

A

$F_2$

B

$C_2$

C

$O_2$

D

$NO$

(JEE MAIN-2019)

Solution

$C_2$ configuration

$\sigma 1{s^2}{\sigma ^*}1{s^2}\sigma 2{s^2}{\sigma ^*}2{s^2}_{\pi 2{p_z}^2}^{\pi 2{p_y}^2}\sigma 2Px$

$C_2^-$ configuration

$\sigma 1{s^2}{\sigma ^*}1{s^2}\sigma 2{s^2}{\sigma ^*}2{s^2}_{\pi 2{p_z}^2}^{\pi 2{p_y}^2}\sigma 2P_x^1$

Standard 11

Chemistry

Share

Similar Questions

In which pair, or pairs, is the stronger bond found in the first species

$(a)$ $O_2^ – ,{O_2}$ $(b)$ ${N_2},N_2^ +$ $(c)$ $NO^+, NO^-$

medium

A simplified application of $MO$ theory to the hypothitical molecule $'OF'$ would give its bond order as :-

medium

Among $\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{~B}_2, \mathrm{C}_2, \mathrm{~N}_2, \mathrm{O}_2^{-}$, and $\mathrm{F}_2$, the number of diamagnetic species is (Atomic numbers: $\mathrm{H}=1, \mathrm{He}=2, \mathrm{Li}=3, \mathrm{Be}=4, \mathrm{~B}=5, \mathrm{C}=6, \mathrm{~N}=7, \mathrm{O}=8, \mathrm{~F}=9$ )

medium

(IIT-2017)

The energy of $\sigma 2{{\rm{p}}_{\rm{z}}}$ molecular orbital is greater than $\pi 2{{\rm{p}}_{\rm{x}}}$ and $\pi 2{{\rm{p}}_{\rm{y}}}$ molecular orbitals in nitrogen molecule. Write the complete sequence of energy levels in the increasing order of energy in the molecule. Compare the relative stability and the magnetic behaviour of the following species : ${{\rm{N}}_2},{\rm{N}}_2^ + ,{\rm{N}}_2^ – ,{\rm{N}}_2^{2 + },$

medium

Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.

easy