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2. Electric Potential and Capacitance
easy
An $\alpha $-particle is accelerated through a potential difference of $200\,V$. The increase in its kinetic energy is.......$eV$
A
$100$
B
$200$
C
$400$
D
$800$
Solution
(c) $KE = QV\, \Rightarrow KE = (2e)\,200\,V = 400\,eV$
Standard 12
Physics
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