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11.Dual Nature of Radiation and matter
easy
An $\alpha$ particle is accelerated through a p.d of ${10^6}$ volt then $ K.E$ . of particle will be .......... $MeV$
A
$ 8$
B
$ 4 $
C
$ 2 $
D
$ 1$
Solution
(c) $K = Q.\Delta V = (2e) \times {10^6}V = 2 \times {10^6}eV = 2M\,eV$
Standard 12
Physics
