- Home
- Standard 11
- Physics
9-1.Fluid Mechanics
medium
An air bubble of diameter $6\,mm$ rises steadily through a solution of density $1750\,kg / m ^3$ at the rate of $0.35\,cm / s$. The co-efficient of viscosity of the solution (neglect density of air) is $..........\,Pas$ (given, $g =10\,ms ^{-2}$)
A
$5$
B
$10$
C
$8$
D
$9$
(JEE MAIN-2023)
Solution

Since the bubble is moving at constant speed the force acting on it is zero.
$B = F _{ V }$
$\frac{4}{3} \pi R ^3 \rho g =6 \pi \eta Rv$
$\eta=\frac{2 R ^2 \rho g }{9 v }=\frac{2 \times\left(3 \times 10^{-3}\right)^2 \times 1750 \times 10}{9 \times 0.35 \times 10^{-2}}=10\,Pas$
Standard 11
Physics