An air bubble of radius $r$ in water is at depth $h$ below the water surface at same instant. If $P$ is atmospheric pressure and $d$ and $T$ are the density and surface tension of water respectively. The pressure inside the bubble will be
An air bubble of radius $r$ in water is at depth $h$ below the water surface at same instant. If $P$ is atmospheric pressure and $d$ and $T$ are the density and surface tension of water respectively. The pressure inside the bubble will be
- A
$P + hdg -(4\pi/r)$
- B
$P + hdg + (2\pi/r)$
- C
$P + hdg -(2\pi/r)$
- D
$P + hdg + (4\pi/r)$
Similar Questions
What is the excess pressure inside a bubble of soap solution of radius $5.00 \;mm$, given that the surface tension of soap solution at the temperature ($20\,^{\circ} C$) is $2.50 \times 10^{-2}\; N m ^{-1}$ ? If an air bubble of the same dimension were formed at depth of $40.0 \;cm$ inside a container containing the soap solution (of relative density $1.20$), what would be the pressure inside the bubble? ($1$ atmospheric pressure is $1.01 \times 10^{5} \;Pa$ ).
What is the excess pressure inside a bubble of soap solution of radius $5.00 \;mm$, given that the surface tension of soap solution at the temperature ($20\,^{\circ} C$) is $2.50 \times 10^{-2}\; N m ^{-1}$ ? If an air bubble of the same dimension were formed at depth of $40.0 \;cm$ inside a container containing the soap solution (of relative density $1.20$), what would be the pressure inside the bubble? ($1$ atmospheric pressure is $1.01 \times 10^{5} \;Pa$ ).
The pressure inside a small air bubble of radius $0.1\, mm$ situated just below the surface of water will be equal to [Take surface tension of water $70 \times {10^{ - 3}}N{m^{ - 1}}$ and atmospheric pressure = $1.013 \times {10^5}N{m^{ - 2}}$]
The pressure inside a small air bubble of radius $0.1\, mm$ situated just below the surface of water will be equal to [Take surface tension of water $70 \times {10^{ - 3}}N{m^{ - 1}}$ and atmospheric pressure = $1.013 \times {10^5}N{m^{ - 2}}$]
The excess pressure due to surface tension in a spherical liquid drop of radius r is directly proportional to
The excess pressure due to surface tension in a spherical liquid drop of radius r is directly proportional to
A spherical drop of water has radius $1\, mm$ If surface tension of water is $70 \times {10^{ - 3}}\,N/m$ difference of pressures between inside and out side of the spherical drop is ........ $N/{m^{ - 2}}$
A spherical drop of water has radius $1\, mm$ If surface tension of water is $70 \times {10^{ - 3}}\,N/m$ difference of pressures between inside and out side of the spherical drop is ........ $N/{m^{ - 2}}$
- [AIIMS 2001]
If two glass plates have water between them and are separated by very small distance (see figure), it is very difficult to pull them apart. It is because the water in between forms cylindrical surface on the side that gives rise to lower pressure in the water in comparison to atmosphere. If the radius of the cylindrical surface is $R$ and surface tension of water is $T$ then the pressure in water between the plates is lower by
If two glass plates have water between them and are separated by very small distance (see figure), it is very difficult to pull them apart. It is because the water in between forms cylindrical surface on the side that gives rise to lower pressure in the water in comparison to atmosphere. If the radius of the cylindrical surface is $R$ and surface tension of water is $T$ then the pressure in water between the plates is lower by