11.Dual Nature of Radiation and matter
medium

An AIR station is broadcasting the waves of wavelength $300$ metres. If the radiating power of the transmitter is $10 kW$, then the number of photons radiated per second is

A

$1.5 \times {10^{29}}$

B

$1.5 \times {10^{31}}$

C

$1.5 \times {10^{33}}$

D

$1.5 \times {10^{35}}$

Solution

(b) $P = \frac{W}{t} = \frac{{nhc}}{{\lambda t}}\,$

$\Rightarrow \,\,\left( {\frac{n}{t}} \right) = \frac{{P\lambda }}{{hc}}$

$ = \frac{{10 \times {{10}^3} \times 300}}{{6.6 \times {{10}^{ – 34}} \times 3 \times {{10}^8}}}$

$ = 1.5 \times {10^{31}}$

Standard 12
Physics

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