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4-1.Newton's Laws of Motion
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An aircraft executes a horizontal loop with a speed of $150\, m/s$ with its wings banked at an angle of $12^o$. The radius of the loop is .......... $km$ $(g = 10\, m/s^2 \; and\; \tan 12^o = 0.2125)$
A$10.6$
B$9.6$
C$7.4$
D$5.8$
(AIIMS-2010)
Solution
The angle of banking, $\tan \theta = \frac{{{v^2}}}{{rg}}$
$⇒$ $\tan 12^\circ = \frac{{{{(150)}^2}}}{{r \times 10}}$
$⇒$ $r = 10.6 \times {10^3}\,m = 10.6\,km$
$⇒$ $\tan 12^\circ = \frac{{{{(150)}^2}}}{{r \times 10}}$
$⇒$ $r = 10.6 \times {10^3}\,m = 10.6\,km$
Standard 11
Physics
