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2. Electric Potential and Capacitance
easy
An alpha particle is accelerated through a potential difference of ${10^6}\,volt$. Its kinetic energy will be......$MeV$
A
$1$
B
$2$
C
$4$
D
$8$
Solution
(b) $K = qV = 2e \times {10^6}\,J = \frac{{2e \times {{10}^6}}}{e}\,eV = 2\,MeV$
Standard 12
Physics