Gujarati
2. Electric Potential and Capacitance
easy

An alpha particle is accelerated through a potential difference of ${10^6}\,volt$. Its kinetic energy will be......$MeV$

A

$1$

B

$2$

C

$4$

D

$8$

Solution

(b) $K = qV = 2e \times {10^6}\,J = \frac{{2e \times {{10}^6}}}{e}\,eV = 2\,MeV$

Standard 12
Physics

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