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2. Electric Potential and Capacitance
easy
A proton is accelerated through $50,000\, V$. Its energy will increase by
A
$5000 \,eV$
B
$8 \times {10^{ - 15}}\,J$
C
$5000 \,J$
D
$50,000\, J$
Solution
(b) Kinetic energy $K = Q.V$ $==>$ $K = (+e) (50000 \,V)$
$= 50000\, eV = 50000 × 1.6 × 10^{-19} \,J = 8 × 10^{-15}\, J$
Standard 12
Physics