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8.Electromagnetic waves
easy
An electromagnetic wave of frequency $\nu = 3.0\,MHz$ passes from vacuum into a dielectric medium with permitivity $\varepsilon = 4.0$. Then
A
Wavelength is doubled and the frequency remains unchanged
B
Wavelength is doubled and frequency becomes half
C
Wavelength is halved and frequency remains unchanged
D
Wavelength and frequency both remain unchanged
(AIEEE-2004)
Solution
Refractive index $ = \sqrt {\frac{{\mu \varepsilon }}{{{\mu _0}{\varepsilon _0}}}} $
Here $\mu$ is not specified so we can consider $\mu$ = $\mu_0$
then refractive index $ = \sqrt {\frac{\varepsilon }{{{\varepsilon _0}}}} = 2$
Speed and wavelength of wave becomes half and frequency remain unchanged.
Standard 12
Physics
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