8.Electromagnetic waves
easy

An electromagnetic wave of frequency $\nu = 3.0\,MHz$ passes from vacuum into a dielectric medium with permitivity $\varepsilon = 4.0$. Then

A

Wavelength is doubled and the frequency remains unchanged

B

Wavelength is doubled and frequency becomes half

C

Wavelength is halved and frequency remains unchanged

D

Wavelength and frequency both remain unchanged

(AIEEE-2004)

Solution

Refractive index $ = \sqrt {\frac{{\mu \varepsilon }}{{{\mu _0}{\varepsilon _0}}}} $

Here $\mu$ is not specified so we can consider $\mu$ = $\mu_0$

then refractive index $ = \sqrt {\frac{\varepsilon }{{{\varepsilon _0}}}} = 2$

Speed and wavelength of wave becomes half and frequency remain unchanged.

Standard 12
Physics

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