Gujarati
1. Electric Charges and Fields
easy

An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be

A

$1.7 \times {10^{ - 11}}\,N/C$

B

$5.0 \times {10^{ - 11}}\,N/C$

C

$5.5 \times {10^{ - 11}}\,N/C$

D

$56 N/C$

Solution

(c) $E = \frac{F}{q} = \frac{{mg}}{e}$ $ = \frac{{9 \times {{10}^{ – 31}} \times 9.8}}{{1.6 \times {{10}^{ – 19}}}} = 5.5 \times {10^{ – 11}}N/C$

Standard 12
Physics

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