An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be
$1.7 \times {10^{ - 11}}\,N/C$
$5.0 \times {10^{ - 11}}\,N/C$
$5.5 \times {10^{ - 11}}\,N/C$
$56 N/C$
Charge $q$ is uniformly distributed over a thin half ring of radius $R$. The electric field at the centre of the ring is
A vertical electric field of magnitude $4.9 \times 10^{5} N / C$ just prevents a water droplet of a mass $0.1\, g$ from falling. The value of charge on the droplet will be ........ $\times 10^{-9} \;C$ $\left(\right.$ Given $\left.g =9.8 m / s ^{2}\right)$
The direction $(\theta ) $ of $\vec E$ at point $P$ due to uniformly charged finite rod will be
Is electric field scalar or vector ? Why ?
A charged oil drop is suspended in a uniform field of $3 \times$ $10^{4} V / m$ so that it neither falls nor rises. The charge on the drop will be $.....\times 10^{-18}\; C$
(take the mass of the charge $=9.9 \times 10^{-15} kg$ and $g=10 m / s ^{2}$ )