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4.Moving Charges and Magnetism
medium
An electron has mass $9 \times {10^{ - 31}}\,kg$ and charge $1.6 \times {10^{ - 19}}C$ is moving with a velocity of ${10^6}\,m/s$, enters a region where magnetic field exists. If it describes a circle of radius $0.10\, m$, the intensity of magnetic field must be
A
$1.8 \times {10^{ - 4}}\,T$
B
$5.6 \times {10^{ - 5}}\,T$
C
$14.4 \times {10^{ - 5}}\,T$
D
$1.3 \times {10^{ - 6}}\,T$
Solution
(b) $B = \frac{{mv}}{{qr}} = \frac{{9 \times {{10}^{ – 31}} \times {{10}^6}}}{{1.6 \times {{10}^{ – 19}} \times 0.1}} = 5.6 \times {10^{ – 5}}\,T$
Standard 12
Physics
