An electron initially at rest, is accelerated | vedclass

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Question

(b) $\frac{1}{2}m{v^2} = eV\,\, \Rightarrow \,\,\frac{e}{m} = \frac{{{v^2}}}{{2V}} = \frac{{{{(8.4 	imes {{10}^6})}^2}}}{{2 	imes 200}}$$ = 1.76 	i

Vedclass · Accepted Answer

$1.76 	imes {10^{11}}C/kg$

Vedclass · Answer

(b) $\frac{1}{2}m{v^2} = eV\,\, \Rightarrow \,\,\frac{e}{m} = \frac{{{v^2}}}{{2V}} = \frac{{{{(8.4 	imes {{10}^6})}^2}}}{{2 	imes 200}}$$ = 1.76 	imes {10^{11}}\,\frac{C}{{kg}}.$

An electron initially at rest, is accelerated through a potential difference of $ 200$ volt, so that it acquires a velocity $8.4 \times {10^6}m/s.$ The value of $e/m$ of electron will be

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