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11.Dual Nature of Radiation and matter
medium
In a parabola spectrograph, the velocities of four positive ions $P,Q,R$ and $S$ are $v_1$, $v_2$, $v_3$ and $v_4$ respectively
A
${v_1} > {v_2} > {v_3} > {v_4}$
B
${v_1} < {v_2} < {v_3} < {v_4}$
C
${v_1} = {v_2} = {v_3} = {v_4}$
D
${v_1} < < {v_2} > {v_3} < {v_4}$
Solution
(a) $\because \;x \propto \frac{1}{{{v^2}}}.$ The ion whose deflection is less, its velocity will be more. From the curve ${x_1} < {x_2} < {x_3} < {x_4}$,
$\therefore {v_1} > {v_2} > {v_3} > {v_4}$.
Standard 12
Physics
