In a parabola spectrograph, the velocities of | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) $\because \;x \propto \frac{1}{{{v^2}}}.$  The ion whose deflection is less, its velocity will be more. From the curve ${x_1} < {x_2} <

Vedclass · Accepted Answer

${v_1} > {v_2} > {v_3} > {v_4}$

Vedclass · Answer

(a) $\because \;x \propto \frac{1}{{{v^2}}}.$ The ion whose deflection is less, its velocity will be more. From the curve ${x_1} < {x_2} < {x_3} < {x_4}$, $ herefore {v_1} > {v_2} > {v_3} > {v_4}$.

In a parabola spectrograph, the velocities of four positive ions $P,Q,R$ and $S$ are $v_1$, $v_2$, $v_3$ and $v_4$ respectively

Similar Questions

Which of the following is not the property of a cathode ray

Which of the following will have the least value of $\frac{q}{m}$

In Thomson spectrograph experiment, four positive ions $P,Q,R$ and $S$ are situated on $Y-X$ curve a shown in the figure

Which scientist invented cathode rays ?

In $1897$, J.J.Thomson invented which particle ?