An electron is moving with a speed of {10^8},m/sec perpendicular to a uniform magnetic field of inte

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4.Moving Charges and Magnetism

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An electron is moving with a speed of ${10^8}\,m/\sec $ perpendicular to a uniform magnetic field of intensity $B$. Suddenly intensity of the magnetic field is reduced to $B/2$. The radius of the path becomes from the original value of $r$

A

No change

B

Reduces to $r / 2$

C

Increases to $2r$

D

Stops moving

Solution

(c) $r \propto \frac{1}{B}$ i.e. $\frac{{{r_1}}}{{{r_2}}} = \frac{{{B_2}}}{{{B_1}}} \Rightarrow {r_2} = \frac{{{B_1}}}{{{B_1}/2}} \times r$=$ 2r$

Standard 12

Physics

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