Gujarati
1. Electric Charges and Fields
medium

An electron of mass ${m_e}$ initially at rest moves through a certain distance in a uniform electric field in time ${t_1}$. A proton of mass ${m_p}$ also initially at rest takes time ${t_2}$ to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio of ${t_2}/{t_1}$ is nearly equal to

A

$1$

B

${({m_p}/{m_e})^{1/2}}$

C

${({m_e}/{m_p})^{1/2}}$

D

$1836$

(IIT-1997) (AIIMS-2015)

Solution

(b) For electron $s = \frac{{eE}}{{{m_e}}} \times t_1^2$, For proton $s = \frac{{eE}}{{{m_p}}} \times t_2^2$
 $\frac{{t_2^2}}{{t_1^2}} = \frac{{{m_p}}}{{{m_e}}}\, \Rightarrow \frac{{{t_2}}}{{{t_1}}} = \sqrt {\frac{{{m_p}}}{{{m_e}}}} = {\left( {\frac{{{m_p}}}{{{m_e}}}} \right)^{1/2}}$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.