2.Motion in Straight Line
medium

એક કણનો વેગ $v = kt,$ જયાં $k = 2m/{\sec ^2}$ તો, પ્રથમ $3 \,sec$ માં કેટલા........$m$ અંતર કાપે?

A

$9$

B

$16$

C

$27 $

D

$36 $

Solution

(a) $S = \int_0^3 {v\;dt} = \int_0^3 {kt\;dt} = \left[ {\frac{1}{2}k{t^2}} \right]_0^3 = \frac{1}{2} \times 2 \times 9 = 9\,m$

Standard 11
Physics

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