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9-1.Fluid Mechanics
normal
An engine pumps water through a hose pipe. Water passes through the pipe and leaves it with a velocity of $2\, m/s$. The mass per unit length of water in the pipe is $100\, kg/m$. ......... $W$ is the power of the engine .
A
$800$
B
$400$
C
$200$
D
$100$
Solution
$ \text { Power } =F v=v\left(\frac{m}{t}\right) v=v^{2}(\rho A v) $
$ =\rho A v^{3}=(100)(2)^{3}=800 W$
Standard 11
Physics