Gujarati
Hindi
9-1.Fluid Mechanics
normal

An engine pumps water through a hose pipe. Water passes through the pipe and leaves it with a velocity of $2\, m/s$. The mass per unit length of water in the pipe is $100\, kg/m$. ......... $W$ is the power of the engine .

A

$800$

B

$400$

C

$200$

D

$100$

Solution

$ \text { Power } =F v=v\left(\frac{m}{t}\right) v=v^{2}(\rho A v) $

$ =\rho A v^{3}=(100)(2)^{3}=800 W$

Standard 11
Physics

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