Two equal drops are falling through air with | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$2 	imes \frac{4}{3}\pi {r^3} = \frac{4}{3}\pi {R^3}$

$R = {2^{1/3}}r$

Now,  ${V_T} \propto {r^2}$

${V_T} = {2^{2/3}} 	imes 5 = {

Vedclass · Accepted Answer

$5 	imes {\left( 4 ight)^{1/3}}\,cm/s$

Vedclass · Answer

$2 	imes \frac{4}{3}\pi {r^3} = \frac{4}{3}\pi {R^3}$

$R = {2^{1/3}}r$

Now,  ${V_T} \propto {r^2}$

${V_T} = {2^{2/3}} 	imes 5 = {4^{1/3}} 	imes 5$ $cm/s$

Two equal drops are falling through air with a steady velocity of $5\, cm/second$. If two drops coalesce to form one drop then new terminal velocity will be

Similar Questions

When a large bubble rises from the bottom of a lake to the surface, its radius doubles. If atmospheric pressure is equal to that of column of water height $H$, then the depth of lake is

A boat carrying a number of large stones is floating in a water tank. What would happen to the water level if a few stones are unloaded into water

The terminal velocity of a small sized spherical body of radius $r$ falling vertically in a viscous liquid is given by the proportionality

A cubical block is floating in a liquid with half of its volume immersed in the liquid. When the whole system accelerates upwards with a net acceleration of $g/3$. The fraction of volume immersed in the liquid will be :-

Two drops of equal radius are falling through air with a steady velocity of $5\,cm/s$. If the two drops coalesce, then its terminal velocity will be