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Question

$2 	imes \frac{4}{3}\pi {r^3} = \frac{4}{3}\pi {R^3}$

$R = {2^{1/3}}r$

Now,  ${V_T} \propto {r^2}$

${V_T} = {2^{2/3}} 	imes 5 = {

Vedclass · Accepted Answer

$5 	imes {\left( 4 ight)^{1/3}}\,cm/s$

Vedclass · Answer

$2 	imes \frac{4}{3}\pi {r^3} = \frac{4}{3}\pi {R^3}$

$R = {2^{1/3}}r$

Now,  ${V_T} \propto {r^2}$

${V_T} = {2^{2/3}} 	imes 5 = {4^{1/3}} 	imes 5$ $cm/s$

Two equal drops are falling through air with a steady velocity of $5\, cm/second$. If two drops coalesce to form one drop then new terminal velocity will be

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