If terminal speed of a sphere of gold (density = 19.5, kg/m^3 ) is 0.2, m/s in a viscous liquid (den

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9-1.Fluid Mechanics

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If the terminal speed of a sphere of gold (density $= 19.5\, kg/m^3$) is $0.2\, m/s$ in a viscous liquid (density $= 1.5\, kg/m^3$), find the terminal speed of a sphere of silver (density $= 10.5\, kg/m^3$) of the same size in the same liquid....... $m/s$

$0.4$

$0.133$

$0.1$

$0.2$

Solution

${V_T} = \frac{{2{r^2}\left( {{d_1} – {d_2}} \right)g}}{{9\eta }}$

$\frac{{{V_{{T_2}}}}}{{0.2}} = \frac{{\left( {10.5 – 1.5} \right)}}{{\left( {19.5 – 1.5} \right)}} \Rightarrow {V_{{T_2}}} = 0.2 \times \frac{9}{{18}}$

$\therefore {V_{{T_2}}} = 0.1\,m/s$

Standard 11

Physics

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normal

If the terminal speed of a sphere of gold (density $= 19.5\, kg/m^3$) is $0.2\, m/s$ in a viscous liquid (density $= 1.5\, kg/m^3$), find the terminal speed of a sphere of silver (density $= 10.5\, kg/m^3$) of the same size in the same liquid....... $m/s$

Solution

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