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10-1.Thermometry, Thermal Expansion and Calorimetry
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An experiment takes $10\, minutes$ to raise the temperature of water in a container from $0\,^oC$ to $100\,^oC$ and another $55\, minutes$ to convert it totally into steam by a heater supplying heat at a uniform rate . Neglecting the specific heat of the container and taking specific heat of water to be $1\, cal / g\,^oC$, the heat of vapourization according to this experiment will come out to be ........ $cal/g$
A
$560$
B
$550$
C
$540$
D
$530$
(JEE MAIN-2015)
Solution
$As\,{p_t} = mC\Delta T$
$So,\,p \times 10 \times 60 = m\,C\,100\,\,\,…\left( i \right)$
$and\,p \times 55 \times 60 = mL\,\,\,\,\,\,\,\,\,…\left( {ii} \right)$
Dividing equation $(i)$ by $(ii)$ we get
$\frac{{10}}{{55}} = \frac{{C \times 100}}{L}$
$\therefore L = 550\,cal/g.$
Standard 11
Physics
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