Heat is being supplied at a constant rate to sphere of ice which is melting at rate of 0.1 ,gm / s .

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Heat is being supplied at a constant rate to the sphere of ice which is melting at the rate of $0.1 \,gm / s$. It melts completely in $100 \,s$. The rate of rise of temperature thereafter will be ............ $^{\circ} C / s$

A

$0.4$

B

$2.1$

C

$3.2$

D

$0.8$

Solution

(d)

$\frac{d Q}{d t}=\frac{d m}{d t} \times L \quad[\because Q=m L]$

$\frac{d Q}{d t}=0.1 \times 80=8 \,cal / gs$

also, $Q=m s \Delta t$

So $\frac{d Q}{d t}=m s \frac{d T}{d t}$

$8=10 \times 1 \times \frac{d T}{d t} \quad[\because$ It melts in $100 \,s$ so total mass of sphere $=0.1 \times 100=10 \,g ]$

$8^{\circ} C / s =\frac{d T}{d t}$

Standard 11

Physics

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