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11.Thermodynamics
easy
An ideal gas is taken around $ABCA$ as shown in the above $P-V$ diagram. The work done during a cycle is

A
Zero
B
$\frac{1}{2}PV$
C
$2 PV$
D
$PV$
Solution
(d) Work done = Area enclosed by the curve
$ = \frac{1}{2}(3V – V)\,(2P – P) = PV$
Standard 11
Physics