11.Thermodynamics
easy

An ideal gas is taken around $ABCA$ as shown in the above $P-V$ diagram. The work done during a cycle is

A

Zero

B

$\frac{1}{2}PV$

C

$2 PV$

D

$PV$

Solution

(d) Work done = Area enclosed by the curve

$ = \frac{1}{2}(3V – V)\,(2P – P) = PV$

Standard 11
Physics

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